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l this month\'s pro lowing table shows what the cost would be for shipping each

ID: 3044890 • Letter: L

Question

l this month's pro lowing table shows what the cost would be for shipping each unit from each factory to each of these customers. Also shown 410 (minimum output. The fol- e are the number of units that will be produced at each factory and level) Benefit 3: Ai + the number of units ordered by each customer A2- A, t 24, 2:30 (minimum A decision now needs to be made about the shipping acceptable level) plan for how many units to ship from each factory to each a. Which category of linear programming problem E b. Formulate and solve a linear programming model customer and does this problem fit? Why? A, 20 A220 A 20 A4 2 0 Formulate and solve the spreadsheet model for this problem. for this problem on a spreadsheet. Summarize this formulation in algebraic form. c. Unit Shipping Cost To From Customer 1 Customer 2 Customer 3 Output Factory 1 Factory 2 600 400 300 units 800 900 200 units $700 600 400 units 500 units Order size 400 units Larry Edison is the director of the Computer Center for 3.18. The Fagersta Steelworks currently is working two College. He now needs to schedule the staffing of the mines to obtain its iron ore. This iron ore is shipped to either It is open from 8 AM until midnight. Larry has monitored of two storage facilities. When needed, it then is shipped on to ge of the center at various times of the day and deter- the company's steel plant. The diagram below depicts this dis- hat the following number of computer consultants are tribution network, where MI and M2 are the two mines, SI and S2 are the two storage facilities, and P is the steel plant. The

Explanation / Answer

Given data on:

Two factories with production output as 400 and 500 units.

Three customers Customer 1, Customer 2 and Customer 3 with order size 300, 200 and 400 respectively. Matrix of unit shipping cost is also given.

This is the problem of Transportation. Define a,b,c,d,e, and f as the number of units shipped from Factory to Customer as shown below.

From

To Customer

C1

C2

C3

Factory 1

a

b

c

Factory 2

d

e

f

We can write transportation cost function as follows:

Z= 600 a+ 800 b+ 700 c+ 400 d+ 900 e+ 700 f

Subject to the constraint:

a+b+c=400

d+e+f=500

a+d=300

b+e=200

c+f=400

a,b,c,d,e,f 0

C1

C2

C3

Output

F1

0 | 600

200 | 800

200 | 700

400

F2

300 | 400

0 | 900

200 | 600

500

Order

300

200

400

In the Table above format of cell is x | y where x is shipment unit (Schedule) and y is unit cost of transportation.

The above solution is Initial Basic Feasible Solution derived using Least Cost Method.

Cost of Transportation = 200X800+200X700+300X400+200X600

                         = 160000+140000+120000+120000 = 540000

One can proceed for optimal solution. The test for testing degeneracy is r+c-1=b

Where r: Number of rows = 2

c: Number of columns =3

b: Number of basic cells. =4

Here condition is valid and therefore the IBFS is not degenerate.

If we apply Modi method to find U and V as follows:

U

0 | 600

200 | 800

200 | 700

0

300 | 400

0 | 900

200 | 600

-100

V

500

800

700

U+V = C for basic (allocated) cell.

For non basic cell compute U+V-C

For both cells these values are -100 and -200, both are negative hence the solution itself is Optimal with minimum cost of shipping.

Hence ship from Factor 1 to customer 2 and customer 3, 200 units each respectively.

Ship from Factor 2 to customer 1 and customer 3, 300 and 200 units respectively.

From

To Customer

C1

C2

C3

Factory 1

a

b

c

Factory 2

d

e

f