The following data are costs (in cents) per ounce for nine different brands of s

Question

The following data are costs (in cents) per ounce for nine different brands of sliced Swiss cheese. 29 61 36 41 70 84 47 52 49 (a) Compute the variance for this data set. (Round your answer to three decimal places.) Compute the standard deviation for this data set. (Round your answer to three decimal places.) (b) If a very expensive cheese with a cost per slice of 150 cents was added to the data set, how would the values of the mean and standard deviation change? The addition of the very expensive cheese would the value of the mean and the value of the standard deviation.

Explanation / Answer

a) SUM = 469 , n= 9 and mean = SUM/n= 469/9= 52.11

Variance

Variance = 2368.889/9= 263.209

Std= sqrt(263.209)= 16.22

b) adding 150cents in the group is

New mean will be = 619/10= 61.9

new variance = 1099.29

std= sqrt(1099.29)= 33.155

NEW STANDARD DEVIATION IS 2 TIMES HIGHER THAN THE PREVIOUS STANDARD DEVIATION.

XI Xi-mean (Xi-mean)^2 29 29-52.11= -23.11 534.12 61 8.89 79.01 36 -16.11 259.561 41 -11.11 123.45 70 17.89 320.02 84 31.889 1016.908 47 -5.11 26.12 52 -0.111 0.012 49 -3.11 9.678 Total 2368.889

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