According to a guide, 47% of cell phone users have only one cell number, 30% hav
ID: 3043207 • Letter: A
Question
According to a guide, 47% of cell phone users have only one cell number, 30% have two numbers, 10% have three numbers, and 13% have four or more numbers. An independent survey of 964 randomly selected cell phone users found that 476 pay for only one number, 331 pay for two numbers, 114 pay for three numbers, and 31 pay for four or more numbers. Conduct a test to determine if the data from the independent survey contradict the percentages reported by the guide. Use =0.1
Determine the null and alternative hypotheses for this test. Choose the correct answer below.
A. Upper H 0 : p1=47%, p2=30%, p3=10%, p4=13% Upper H Subscript a Baseline :Ha: At least one of the multinomial probabilities does not equal its hypothesized value.
B. Upper H 0 : p2p3p4 Upper H Subscript a Baseline :Ha: At least one of the multinomial probabilities equals its hypothesized value.
C. Upper H 0 :p1=p2=p3=p4 Upper H Subscript a Baseline :Ha: p 1 not equals p 2 not equals p 3 not equals p 4p1p2p3p4
Now find the test statistic.
2equals=
Determine the p-value.
Choose the correct conclusion below.
Fail to reject Upper H 0H0. There is sufficient evidence that the data from the survey contradict the percentages reported by the guide.
Reject Upper H 0H0. There is sufficient evidence that the data from the survey contradict the percentages reported by the guide.
Fail to reject Upper H 0H0. There is insufficient evidence that the data from the survey contradict the percentages reported by the guide.
Reject Upper H 0H0. There is insufficient evidence that the data from the survey contradict the percentages reported by the guide
Explanation / Answer
Answer:
According to a guide, 47% of cell phone users have only one cell number, 30% have two numbers, 10% have three numbers, and 13% have four or more numbers. An independent survey of 964 randomly selected cell phone users found that 476 pay for only one number, 331 pay for two numbers, 114 pay for three numbers, and 31 pay for four or more numbers. Conduct a test to determine if the data from the independent survey contradict the percentages reported by the guide. Use =0.1
Determine the null and alternative hypotheses for this test. Choose the correct answer below.
Answer: A. Upper H 0 : p1=47%, p2=30%, p3=10%, p4=13% Upper H Subscript a Baseline :Ha: At least one of the multinomial probabilities does not equal its hypothesized value.
B. Upper H 0 : p2p3p4 Upper H Subscript a Baseline :Ha: At least one of the multinomial probabilities equals its hypothesized value.
C. Upper H 0 :p1=p2=p3=p4 Upper H Subscript a Baseline :Ha: p 1 not equals p 2 not equals p 3 not equals p 4p1p2p3p4
Now find the test statistic.
2equals=82.278
Determine the p-value. P=0.0000
Choose the correct conclusion below.
Fail to reject Upper H 0H0. There is sufficient evidence that the data from the survey contradict the percentages reported by the guide.
Answer: Reject Upper H0. There is sufficient evidence that the data from the survey contradict the percentages reported by the guide.
Fail to reject Upper H 0H0. There is insufficient evidence that the data from the survey contradict the percentages reported by the guide.
Reject Upper H 0H0. There is insufficient evidence that the data from the survey contradict the percentages reported by the guide
Total sample size is 952
Goodness of Fit Test
observed
expected
O - E
(O - E)² / E
476
447.440
28.560
1.823
331
285.600
45.400
7.217
114
95.200
18.800
3.713
31
123.760
-92.760
69.525
Total
952
952.000
82.278
82.278
chi-square
3
df
0.0000
p-value
Goodness of Fit Test
observed
expected
O - E
(O - E)² / E
476
447.440
28.560
1.823
331
285.600
45.400
7.217
114
95.200
18.800
3.713
31
123.760
-92.760
69.525
Total
952
952.000
82.278
82.278
chi-square
3
df
0.0000
p-value
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