This Question: 2 pts he probability of conceiving a git, In the study 460 babies

Question

This Question: 2 pts he probability of conceiving a git, In the study 460 babies ware bom, and 253 of them were girts. Use the sample data to percentage of girls bom. Based on the result, does the method appear to be effective? A dlinical trial losts a mothod designed to increase construct a 99% confidence interval estimate of the Dpc(Round to three decirnal places as needed.) Does the method appear to be effective? O No, the proportion of girls is not significantly different from 0.5 O Yes, the proportion of giris is significantly different from 0.5 nt Click to select your answerls).

Explanation / Answer

Given p^ = 253/460

n = 460 z for 99% = 2.576

Lower limit of the interval = p^ - z (p^ * (1 - p^) / n)

= 253/460 - 2.576 * (253/460 * (1 - 253/460) / 460)

= 0.490.

Upper limit of the interval = p^ + z (p^ * (1 - p^) / n)

= 253/460 + 2.576 * (253/460 * (1 - 253/460) / 460)

= 0.610.

The confidence interval is (0.490, 0.610).

The upper limit is indeed significantly different from 0.5 while the lower limit is close. Therefore, the answer is:

Yes, the proportion of girls is significantly different from 0.5.

Related Questions

Navigate

• Browse (All)
• Browse T
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.