A 1.24 M solution of KI has a density of 1.15 g/cm3. Assume 1.00 liter of 1.24 M

Question

A 1.24 M solution of KI has a density of 1.15 g/cm3. Assume 1.00 liter of 1.24 M KI solution. The mass of 1.00 L of solution is grams. The number of grams of Kl in the 1 liter is grams. The number of grams of water in the 1 L is grams. The molality of the Kl solution is molal. The molal freezing point depression constant for water in kg/molal. The van't Hoff factor for complete dissociation is complete dissociation of Kl the freezing point depression is the actual freezing point depression is -4.46 deg C, the van't Hoff factor value is deg C . For deg C. If and the percent of dissociation is (2 S.F.) Molality is moles of solute per of solvent.

Explanation / Answer

Ans :

Density = mass / volume

1.15 = m / 1

mass = 1.15 kg or 1150 grams

Molarity = number of moles of KI / volume of solution in L

1.24 = n / 1

n = 1.24

So mass of KI in grams = 1.24 x 166.0028 = 205.8 grams

Number of grams of water = 1150 - 205.8 = 944.2 grams

Molality = no. of moles of KI / mass of water in kg

m = 1.24 / 0.9442

= 1.31 m

The molal freezing point depression constant for wateer is 1.86 deg C kg/molal.

The van't hoff factor for complete dissociation is 2.

Freezing point depression = i x kf x m

= 2 x 1.86 x 1.31

= -4.87oC

Since actual freezing point depression = -4.46

4.46 = i x 1.86 x 1.313

i = 1.83

Percent of dissociation = (1.83 / 2) x 100 = 91 %

Molality is moles of solute per kilogram of solvent .

So here , putting the values from the above calculations in the blanks below ...

A 1.24 M solution of KI has a density of 1.15 g/cm3.

Assume 1.00 liter of 1.24 KI solution. The mass of 1.00 L solution is 1150 grams. The number of grams of KI in the 1 liter is 205.8 grams. The number of grams of water in the 1 L is 944.2 grams. The molality of KI solution is 1.313 molal. The molal freezing point depression constant for water is 1.86 deg C kg/molal. The van't hoff factor for complete dissociation is 2. For complete dissociation of KI the freezing point depression is -4.87 deg C. If the actual freezing point depression is -4.46 deg C , the van't hoff factor value is 1.83 and the percent of dissociation is 91%.

Molality is moles of solute per kilograms of solvent.

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