A 30 cM tall plant was crossed with a 10 cM tall plant and the F1 were all 20 cM
ID: 3042426 • Letter: A
Question
A 30 cM tall plant was crossed with a 10 cM tall plant and the F1 were all 20 cM tall. When two of these F1 plants were crossed, the progeny were:
30 cm
4
25 cm
15
20 cM
23
15 cM
17
10 cM
6
TOTAL
65
Using chi-square goodness of fit, test the hypothesis that height in this plant is determined by two equally additive genes such that each "capital allele" adds 5 cM to base height of 10 cM. That is, test the hypothesis that these number represent a 1:4:6:4:1 ratio and answer the following questions:
What is the value of 2? (ZERO decimal places)
30 cm
4
25 cm
15
20 cM
23
15 cM
17
10 cM
6
TOTAL
65
Explanation / Answer
here null hypothesis: Ho: proportion are in the ration 1:4:6:4:1 or (1/16):(1/4):(3/8):(1/4):(1/16)
Ha: Distribution is different from given ratio
applying chi square goodness of fit test:
from above value of 2 =1.133 (~ 1 with ZERO decimal places)
(please revert if there are other parts for this
observed Expected residual Chi square x Probability(p) Oi Ei=total*p Ri=(Oi-Ei)/Ei R2i=(Oi-Ei)2/Ei 30 cm 1/16 4.000 4.1 -0.03 0.00 25 cm 1/4 15.000 16.3 -0.31 0.10 20 cm 3/8 23.000 24.4 -0.28 0.08 15 cm 1/4 17.000 16.3 0.19 0.03 10 cm 1/16 6.000 4.1 0.96 0.92 total 1 65 65 0.528 1.133Related Questions
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