Suppose that a survey reported that 51% of respondents favored gun control, with

Question

Suppose that a survey reported that 51% of respondents favored gun control, with a margin of error of ±2 percentage points.

(a) What was the approximate size of the sample, n? (Round answer to the nearest whole number.) n = _______________

(b) What is an approximate 95% confidence interval for the percentage of the corresponding population who favor gun control? ( ___________, ______________ )%

(c) Write a statement interpreting the interval you found in part (b) that could be understood by someone with no training in statistics. A survey found that 51% of those asked favor gun control. This was based on a sample of about ___________ individuals, but the results indicate that it is likely that between ____________ % and __________ % of the population favors gun control.

Explanation / Answer

a)

b)

approximate 95% confidence interval =(51-2 =49 , 51+2 =53) %

c)

This was based on a sample of about 2400 individuals, but the results indicate that it is likely that between 49 % and 53% of the population favors gun control.

here margin of error E = 0.02 for95% CI crtiical Z          = 1.9600 estimated proportion=p= 0.5100 required sample size n =         p*(1-p)*(/E)2= 2400.00

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