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MAA Logged in as 22929. Log Out WOrk MATHEMATICAL ASSOCIATION OF AMERICA webwork klein, apstatistics 10.4-hypotheses-test-for-a-population-mean-13 10.4 Hypotheses Test for a Population Mean: Problem 13 l pre Up- Entered |Answer Preview Result 0.4545 0.4545correct 0.4545 0.4545 incorrect -0.4545 0.4545 incorrect correct At least one of the answers above is NOT correct. (1 pt) Test the claim that for the population of statistics final exams, the mean score is -79. using alternative hypothesis that the mean score is different from -79. Sample statistics include n = 25, x = 80, and S 11 . Use a significance level of -0.01 . (Assume normally distributed population.) The test statistic is 4545 The positive critical value is 4545 The negative critical value is -4545 The conclusion is O A. There is sufficient evidence to reject the claim that the mean score is equal to 79 B. There is not sufficient evidence to reject the claim that the mean score is equal to 79 Note: You can earn partial credit on this problem.

Explanation / Answer

Using Mintab:

One-Sample Z

Test of mu = 79 vs not = 79
The assumed standard deviation = 11

N Mean SE Mean 90% CI Z P
25 80.00 2.20 (76.38, 83.62) 0.4545 0.649

Test statistic = 0.4545

The z-critical values for a two-tailed test, for a significance level of lpha =0.01

zc = -2.58 and  zc=2.58

P-value > alpha or we can say Critica value > test statistic , we do not reject the null hypothesis. B. option is correct.

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