ezto.mheducati tpx value 10.00 points The customer service department for a whol

Question

ezto.mheducati tpx value 10.00 points The customer service department for a wholesale electronics outlet claims that 80 percent of all customer complaints are resolved to the random sample of 18 customers who have filed complaints is selected of the customer in order to t (b) Find each of the following if we assume that the claim is true: (Do not round intermediate calculations. Round final answers to 4 decimal places) 1 Plxs 13) 2. Px> 10) 3. Px 2 14) 0 4509 09873 0.1837 (c) Suppose that of the 18 customers selected, 9 have had their complaints resolved satisfactorily. Using part b, do you believe the claim of 80 percent satisfaction? Explain 7 if the claim is true, then Px s 9) is very smal No Hints References eBook & Resources

Explanation / Answer

n = 18

p = 0.8

1) P(X < 13) = 1 - P(X > 13)

= 1 - (P(X = 14) + P(X = 15) + P(X = 16) + P(X = 17) + P(X = 18))

= 1 - (18C14 * (0.8)14 * (0.2)4 + 18C15 * (0.8)15 * (0.2)3 + 18C16 * (0.8)16 * (0.2)2 + 18C17 * (0.8)17 * (0.2)1 + 18C18 * (0.8)18 * (0.2)0)

= 1 - 0.716 = 0.284

2) P(X > 10) = P(X = 11) + P(X = 12) + P(X = 13) + P(X = 14) + P(X = 15) + P(X = 16) + P(X = 17) + P(X = 18)

                     =18C11 * (0.8)11 * (0.2)7 + 18C12 * (0.8)12 * (0.2)6 + 18C13 * (0.8)13 * (0.2)5 + 18C14 * (0.8)14 * (0.2)4 + 18C15 * (0.8)15 * (0.2)3 + 18C16 * (0.8)16 * (0.2)2 + 18C17 * (0.8)17 * (0.2)1 + 18C18 * (0.8)18 * (0.2)0 = 0.9837

3) P(X > 14) = P(X = 14) + P(X = 15) + P(X = 16) + P(X = 17) + P(X = 18)

                     = 18C14 * (0.8)14 * (0.2)4 + 18C15 * (0.8)15 * (0.2)3 + 18C16 * (0.8)16 * (0.2)2 + 18C17 * (0.8)17 * (0.2)1 + 18C18 * (0.8)18 * (0.2)0 = 0.716

4) P(9 < x < 12) = P(X = 9) + P(X = 10) + P(X = 11) + P(X = 12)

                          = 18C9 * (0.8)9 * (0.2)9 + 18C10 * (0.8)10 * (0.2)8 + 18C11 * (0.8)11 * (0.2)7 + 18C12 * (0.8)12 * (0.2)6 = 0.132

5) P(X < 9) = 1 - P(X > 9)

                   = 1 - (P(X = 10) + P(X = 11) + P(X = 12) + P(X = 13) + P(X = 14) + P(X = 15) + P(X = 16) + P(X = 17) + P(X = 18))

        = 1 - (18C10 * (0.8)10 * (0.2)8 + 18C11 * (0.8)11 * (0.2)7 + 18C12 * (0.8)12 * (0.2)6 + 18C13 * (0.8)13 * (0.2)5 + 18C14 * (0.8)14 * (0.2)4 + 18C15 * (0.8)15 * (0.2)3 + 18C16 * (0.8)16 * (0.2)2 + 18C17 * (0.8)17 * (0.2)1 + 18C18 * (0.8)18 * (0.2)0)

= 1 - 0.9957 = 0.0043

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