A and b A child playing a carnival game successfully knocks down three milk bott

Question

A and b A child playing a carnival game successfully knocks down three milk bottles. As a result, he gets to randomly select one prize from each of four dark colored bags. The prizes in the bags are indicated in the table below with some bags containing more prizes than o thers a. Find the total number of all possible combinations of prizes that can be selected Items Contained in Each Bag Bag 2 Bag 4 Bag 1 Ball Water Gun Bag 3 Bear Pin Wheel Toy Dog Paddle Ball from the four bags. Bracelet Jump Rope b. What is the probability of the final prize selection containing both a ball and a bracelet? Show work!

Explanation / Answer

(a)

First bag has three options so one prize from this bag can be selected in C(3,1)= 3 ways.

Second bag has three options so one prize from this bag can be selected in C(3,1)= 3 ways.

Third bag has two options so one prize from this bag can be selected in C(2,1)= 2 ways.

Fourth bag has one option so one prize from this bag can be selected in C(1,1)= 1 ways.

Therefore total number of possible selection is 3*3*2*1 = 18

Answer: 18

(b)

Possible number of combination with ball and bracelet is : 1*1*2*1 = 2

So the probability that final prize containing both a ball and a bracelet is:

2 / 18 = 0.1111

Answer: 0.1111

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