1.Calculate the mass % of solute in a solution made by dissolving 1.199 g of sol
ID: 304145 • Letter: 1
Question
1.Calculate the mass % of solute in a solution made by dissolving 1.199 g of solute in 78.686 g of water. Provide your response to three digits after the decimal.
2.
What is the experimental molar mass of a solute if the freezing point of a solution containing 8.970 g of solute in 78.489 g of naphthalene is 56.358 °C? Potentially useful information is provided in the table below. Provide you response to three digits after the decimal.
3.
What is the boiling point of a solution of 5.519 g of solute (molar mass = 50.060 g/mol) in 158.426 g of solvent? (Kb = 0.728 °C/; Tb° = 98.883 °C).
Provide your response to three digits after the decimal. ____ °C
4.
What would be the freezing point of a solution containing 9.466 g of biphenyl (C12H10) dissolved in 95.580 g of naphthalene? Relevant information is provided below. Provide your response to three digits after the decimal.
5.How many grams of water are needed to dissolve 52.719 g of solute (molar mass = 89.310 g/mol) in order to prepare a 0.351 m solution? Provide your response to three digits after the decimal.
solvent freezing point (°C) Kf (°C/m) boiling point (°C) Kb (°C/m) naphthalene (C10H8) 80.6 6.9 218 --Explanation / Answer
Ans 1 :
Mass % = (mass of solute / mass of solution ) x 100
mass of solution = mass of solute + mass of solvent
= 1.199 +78.686
= 79.885 g
So mass % = ( 1.199 / 79.885) x 100
= 1.501 %
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