Show your solution for the following. You are planning a trip and A, B, C, D, E,
ID: 3040352 • Letter: S
Question
Show your solution for the following.
You are planning a trip and A, B, C, D, E, and F wish to join you. However C and D do not get on well together, and neither do A and E. B does not mind going with either A or C, but would not go if both join.
a) How many ways can you take your friends with your friends on a trip if your budget is only good for four people including yourself?
b) What is the probability that C will be included as one of the three companions if F will be taken out from the choices?
Explanation / Answer
Total people including you are = 6 + 1 = 7
C and D do not get on well together therfore take one between this two ( take D )
A and E do not get on well together therfore take one between this two ( take E )
B does not mind going with either A or C, but would not go if both join (take B )
Therefore total coming people are = you + F + B + D + E
= 5 People
But we have budget is only good for four people including yourself
therfore you want to take 3 people from this 4
Therfore use permutation for arrangments :
n = 4 !
r = 3 !
a) No. of ways can you take your friends = 4 ! / ( 4 - 3 ) !
= 24
b) Probability that C will be included as one of the three companions if F will be taken out from the choices.
Total people including you are = 5 + 1 = 6 ( F is not )
C and D do not get on well together therfore take one between this two ( take C )
A and E do not get on well together therfore take one between this two ( take E )
B does not mind going with either A or C, but would not go if both join (take B )
Therefore total coming people are = you + B + C + E
= 4 People
And you have the budget of 4 people with including you. and selected people is also 4 with including C and exclude D.
Total possible way using permutation = 4(P)4 = 24
Probability = 4(P)4 / 4(P)4
= 24/24
= 1
Probability that C will be included as one of the three companions if F will be taken out from the choices is one ( 1 ).
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