TruTak mics for Cortand C O Not secure | www.webassign dep 18222604r04 The May 1

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TruTak mics for Cortand C O Not secure | www.webassign dep 18222604r04 The May 1, 2009, issue of a certain publication reported the following home sale amounts for a sample of homes in Alameda, CA that were sold the previous manith 593 816 570 006 355 1,289 406 545 553 684 (a) Caldate and Interpret the sample mean and median. The sample mean is x- 8417- thousand dollars and the sample medan is i- sos s-406-545** and that but the sies were for less than the medan· ka, whie hlae more than the man thousand dollars. This means that the average i price. (b) Suppose the 6th observation had been 985 rather than 1,2es, blow would the mn median dange? Changing that one value has no effect on the sample mean but lowers the sample median. 0 Changing that one value has no eflect on the sample mean but raises the sample medan. Changing that one vahue has eo dea on either thn sample mean nor the sample medan. e Changing that one value lowers the sample mean but has no effect on the sample medlan. 0 Changing that one value raises the sample mean but has no effect on the sample edian (c) Calolne a 20% trimmed mean by first trimming thn two smallest and two largest bsengers (Round your answer to the nearest hundred dollars ) te) Calculate . 15% t mmed mean. CRound your answer to the nearest hundred dolars.) ,3ppti TOSHIBA

Explanation / Answer

10 entries are there

355 406 545 553 570 593 606 684 816 1289

4.c)

For 20% trimmed mean, remove 2 max and minimum entries and calculate mean

= 1/6 * (545 + 553 + 570 + 593 + 606 + 684)

= 591.83

4.d)

For 15% trimmed mean, remove minimum and maximum and take 0.5 of 2nd minimum and 2nd maximum

= 1/7 * (545 + 553 + 570 + 593 + 606 + 684+ 0.5(406+816))

= 594.57

5.b)

In order to keep the median same, we should make sure that the largest term is not affecting median

So we can decrease it till median value.Here, we are taking avg of 1.009 and 1.038 to find median (as even number of data) so in order to keep median same we can decrease largest value till 1.038.

If we decrease it more that that then median will decrease

Thus, maximum reduction possible = 1.359-1.038 = 0.321

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