X100 9. Tetrahydrocannabinal (THC), an active ingredient of martuans, has the mo

Question

X100 9. Tetrahydrocannabinal (THC), an active ingredient of martuans, has the molecular e its percent composition by element. 84? C21H3002. Calculat 10. what is the empirical formula of a compound that is 32.79% Na, 13.02% Al, and 54.19% n 11. When 10.0 g of a pure compound was analyzed, it was found to contain 3.65 g of K, 3.33 g of a, and 3.02 g of O. Determine the empirical formula of the compound 12. A molecular compound contains 92.3% C and 7.7% H. What is the molecular formula if it has a molecular mass of 78.1 amu.

Explanation / Answer

9) formula = C21H30O2

     molarmass = 21*12+30*1+2*16 = 314g/mol

% composition of C = (21*12)/314*100 = 80.2%

% composition of H = 30/314*100 = 9.55%

% composition of O = 100-(80.2+9.55)= 10.25%

10)

Na = 32.79/23 = 1.425

Al = 13.02/27 = 0.482

F = 54.19/19 = 2.85

simplest ratio

Na = 1.425/0.482 = 3

Al = 0.482/0.482 = 1

F = 2.85/0.482= 6

simplest whole number ratio: Na:Al:F = 3:1:6

empirical formula= Na3AlF6

11)

K = 3.65 / 39 = 0.094 mol

Cl = 3.33/35.5 = 0.094 mol

O = 3.02/16 = 0.19 mol

simplest ratio

K = 0.094/0.094 = 1

Cl = 0.094/0.094 = 1

O = 0.19/0.094 = 2

simplest whole number ratio: K:CL:O = 1:1:2

empirical formula= KClO2

12) C = 92.3/12 = 7.7

        H = 7.7/1 = 7.7

simplest rati
C = 7.7/7.7 = 1

H = 7.7/7.7 = 1

simplest whole number ratio: C:H = 1:1

empirical formula = CH

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