Solve the problem, rounding the answer as appropriate. Assume that \"pure domina

Question

Solve the problem, rounding the answer as appropriate. Assume that "pure dominant" describes one who has two dominant genes for a given trait; "pure recessive" describes one who has two recessive genes for a given trait; and "hybrid" describes one who has one of each. In a population, 70 70% of females are pure dominant, 20 20% are hybrid, and 10% are pure recessive. If a pure recessive male mates with a random female and their first offspring has the dominant trait, what is the probability that the female is pure dominant?

Explanation / Answer

70% females are puredominant

so , 30% males are puredominant

20% females are hybrid

so , 80 % males are hybrid

10 % females are pure recessive

so, 90% males are pure recessive

probability that female is pure dominant = .70 / .90

= 0.77

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