You throw a ball straight up from a rooftop 30 feet high with an initial speed o

Question

You throw a ball straight up from a rooftop 30 feet high with an initial speed of 64 feet per second The function s(t) = 16t^2 + 64t + 30 models the ball's height above the ground, s(t), in feet, t seconds after it was thrown. During which time period will the ball's height exceed that of the rooftop? When will the bal exceed the height of the rooftop? Between 0 and 5 seconds, excluding t = 0 and t = 5. Between 0 and 4 seconds, including t = 0 and t = 4. Between 0 and 5 seconds, including t = 0 and t = 5. Between 0 and 4 seconds, excluding t = 0 and t = 4.

Explanation / Answer

s(t) = -16t^2+64t + 30

rooftop height = 30 mt

s(t) >30

-16t^2+64t + 30 >30

-16t^2 +64t >0

t(-16t +64) >0 ; t(-t+4)>0

0<t< 4 .It means t = 0 and 4 sec excluding 0 and 4

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