s. (FE Lf the contamination of Puget Sound was suddenly stopped. it has been est
ID: 3032731 • Letter: S
Question
s. (FE Lf the contamination of Puget Sound was suddenly stopped. it has been estimated thatthe amount of contaminants remaining at time t would be given by the formula P(t) e oroossz where t is measured years ppm 36.500 at the time further in and 36,500 (parts per million) is the contamination level contamination stops. a) How much pollution remains after 100 years? pot) 30500e round to nearest bundeedth units 3 600 2.1913 24 (og 3929 many years would it take until only 40% of the contaminants remain in Puget Sound b) How 40-50 00 600 30 500 round to nearest hundredth uats c) According to the model bove, will the Puget Sound ever be pollution free? YES No circle your answer t 5) A storage tank contains radium-226, a radioactive elementExplanation / Answer
Your solution to part a seems correct. The only reason for disparity could be the parts per million factor for which pollution and contaminants may differ.
Note: Formula for contaminants has been given but data for pollution is being asked.
For part B) you are heading in the right direction. 40% of 36500 = 14600 which is equal to
14600 = 36500 e -0.00382t
Take log on both sides: 9.588 = 10.50 -0.00382t
Thus 0.00382t = 10.5 - 9.588
t= 0.912/ 0.00382 = 238.74 years
Thus time after which only 40% contaminant remaining in Puget sound is 238.74 years
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