#20 final biology Compatibility Mode out References Mailings Review View HelpO T

Question

#20 final biology Compatibility Mode out References Mailings Review View HelpO Tell me what you want to do Emphasis Heading 1 Normal Strong Paragraph Styles BIO 111, FINAL EXAM, BTO 111 / Disk 40s 17. A codon: a. contains instructions for placement of one amino acid. b. contains instructions for the assembly of an entire protein. c. is a gene. d. is a sequence of 4 bases on mRNA e. none of the above 18. Ribosomes are composed of d. lipids and mRNA e. rRNAs and tRNAs small proteins a. b. c. proteins and tRNAs proteins and rRNAs If a segment of DNA had the sequence G-A-C-C-G-A-A-A-G, the complementary to it would have the sequence: 19. er RNA a. G-A-C-C-G-A-A-A-G b. C-T-G.GC-T-T-T-C. c. CU-GG-C-U-U-U-C. d. A-G-T-T-A-G-G-G-A e. A-G-U-U-A-G-G-G-A. 20. The base sequence CUA on mRNA is recognized by which sequence of nucleotides on tRNA? a. GAU b. CAU c. GAT d. GTT e. CTA 26

Explanation / Answer

Ans 18 proteins and rRNA. Ribosomes are made up of two subunits. Small and large.

And 20 base pairing are always comolemencomp.

A paires with T. ( In case of RNA it is U)

G pairs with C.

It this case since we are dealing with RNA C pairs with G.

U pairs with A

And A pairs with U

Hence the answer is GAU.

And 16 mRNA is single stranded. It has to be single stranded to facilitate the binding of tRNA to it. If it was double stranded there would be no binding sites for tRNA

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