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ID: 3025391 • Letter: 1

Question

16% D Thu 10:08 ome File Edit View History Bookmarks People Window Help O www.web O www.webassign.net/v4cgi/student/practice.tpl 3 Ex3 Rev x c Search Textbox Evaluate The Ex R Panzoid x CHome I chegg x D about blank x download wee x Tu e O webassign.net/web/Student/Assignment-Res ?dep 15900354 Q8 Need Help? Master it 15. O -1 points SAlgTrig4 7.4.038. My Notes o Ask Find all solutions of the given equation. (Enter your answers as a comma-separated list. Let k be any integer. Round terms to two decimal places where appropriate) rad 16. O ar1 points I Previous Answers SAgTrig4 74.050. D My Notes o Ask solve the given equation. (Enter your answers as a comma-separated list. Let k be any integer. Round terms to three decimal places where appropriate. If no solution, enter NO SOLUTION.)

Explanation / Answer

Solution:(1)

csc2() - 2 = 0

[1/sin()]2 = 2
sin2() = 1/2
sin() = ± 1/
2

First case: sin() = - 1/
2
= 2 - (/4) = 7/4
= + (/4) = 5/4

Second case: sin() = 1/2
= /4
= - (/4) = 3/4

Solution = { /4 ; 3/4 ; 5/4 ; 7/4 ;} ,
= /4 ± k/2 for some integer k.

Solution:(2)

3 tan3 = tan
3tan3 - tan = 0
tan(3tan2-1) = 0
tan = 0 and tan = ±1/3

tan() is 0 whenever the y component is 0, so at the origin and at :    ± k for some integer k.

tan() is 1/3 when x-component is 3/2 and y-component is 1/2.

so that y/x (tan) is (1/2) / (3/2) = 1/3

This happens at /6 and 7/6, so then:   /6 ± k for some integer k.

So = [ ± k, /6 ± k ]

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