A plant manager randomly divides her employees into two groups. One group (Group
ID: 3023591 • Letter: A
Question
A plant manager randomly divides her employees into two groups. One group (Group A) includes 32 employees and the second one (Group B) includes 30 employees. After dividing the employees, the manager wants to confirm that the two groups are indeed similar in performance. He hypothesizes that there is no statistically significant difference between the two groups. To compare the two groups, the plant manager use ratings given by the employees' front-line supervisors at the end of the previous year. The rating scale ranges from 5 (excellent employee) to 1 (on the brink of termination). Using these ratings, the manager conducts a t test to determine whether the two groups are similar. The results are as follows:
Group
n
Mean
SD
t
A
32
3.66
1.31
2.008
B
30
3.00
1.26
tcrit(.05,df)=2.0;
tcrit(.02,df)=2.390;
t crit(.01 ,df)=2.660
Which t test was used and why?
What were the degrees of freedom?
What are the manager's conclusions? Explain.
Group
n
Mean
SD
t
A
32
3.66
1.31
2.008
B
30
3.00
1.26
tcrit(.05,df)=2.0;
tcrit(.02,df)=2.390;
t crit(.01 ,df)=2.660
Explanation / Answer
A) TWO TAILED T TEST HAS BEEN USED IN THIS BECAUSE IN THIS CASE WH HAVE TWO GROUPS AND THAT TOO BE ANALYSED WITH THE SIMILARITY TO THE OTHER
B) DEGREE OF FREEDON FOR 1 GROUP = 32-1 =31
DEGREE OF FREEDOM FOR OTHER GROUP = 30-1 = 29
C) THE MANAGER WILL CONLCUDE THAT THE TWO GROUPS ARE NOT SIMILAR AS THE CRTITICAL VALUES FOR BOTH THE GROUPS ARE DIFFERENT AND THE DIFFERENCE IS AROUND 0.390 WHICH ACCOUNTS FOR 39%
Related Questions
drjack9650@gmail.com
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.