3.6 A problem with a telephone line, which prevents a customer from receiving or

Question

3.6 A problem with a telephone line, which prevents a customer from receiving or making calls, is disconcert- ing both to the customer and the telephone company These problems can be of two types: those that are located inside a central office, and those that are located on lines between the central office and the customer's equipment. The following data represent samples of 20 problems reported to two different offices of a telephone company and the time taken to clear these problems from the customers' lines (in minutes). problems from the customers' lines (in minutes. Central Office I-Time to Clear Problems 1.48 1.75 0.78 2.85 0.52 1.60 4.15 3.971.48 3.10 1.020.53 0.935 1.60 080 1.058 632 3.930 5.45 0.97 Central Office II-Time to Clear Problems 7.53 3.75 0.10 1.10 0.60 052 3.30 7.55 3.75 0.10 1.10 0.60 0.52 3.30 2.10 0.58 4.02 3.75.51.92 0.0 1.53" 4.2300.08 1.48 1.65,>0.72 5 PHONE For each of the two central office locations, do all of the following: (a) Compute the (1) arithmetic mean, (6) midhinge, (2) median, (3) midrange, (4) first quartile, (9) variance, (5) third quartile, (10) standard deviation. (7) range, (8) interquartile range.

Explanation / Answer

c). Since, from Office-I  data the value of Mean> Median,so we conclude that it is Positive skeweness.

  Since, from Office-II data the value of Mean> Median,so we conclude that it is Positive skeweness.

d) By observation of above computation,we conclude that there is no similarities in the data, it shows slight variation.

e) By replacing 27.55 in office-II, output from the changed data is changing. Proof is as follows

Office-I Office-II Mean 2.21 2.0115 Median 1.54 1.505 midrange 3.42 3.814 First quartile 0.94 0.6 Third quartile 3.7225 3.6375 Midhinge 3.93 1.92 Range 5.8 7.47 Interquartilerange 2.7825 3.0375 Varience 2.804074 3.3996 Standard deviation 1.67453 1.843807

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