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Insurance companies have determined that US males between the ages of 16 and 24,

ID: 3023174 • Letter: I

Question

Insurance companies have determined that US males between the ages of 16 and 24, drive an average of 10,718 miles each year with a standard deviation of 3763 miles. Assume the data is normally distributed. For a randomly selected male in that age group, find the probability that he drives less than 12,000 miles per year. 23. A company that manufactures sleeping bags says that the average amount down in an adult sleeping bag is 32 oz. with a standard deviation of 0.9 cz. is the probability that a bag chosen at random has more than 33.2 oz. of down of 24. The heights of six-year old girls are normally distributed with a mean of 117.80 cm and a standard deviation of 5.52 cm. Find the probability that a randomly selected six-year girl has a height between 117.80 cm and 120.56 cm. 25. The average heating bill for a residential area is $123 for the month of November with a standard deviation of $8. If the amounts of the heating bills are normally distributed, find the probability that the average bill for a randomly selected resident is more than $125 26. An IQ test has a mean of 100 with a standard deviation of 15. What is the probability that a randomly selected adult has an IQ between 85 and 115? deviation of 1 hour. What percent of adults spend more than 6 hours per week on their home computer? 27. The average adult spends 5 hours per week on a home computer, with a standard

Explanation / Answer

22.

We first get the z score for the critical value. As z = (x - u) / s, then as          
          
x = critical value =    12000      
u = mean =    10718      
          
s = standard deviation =    3763      
          
Thus,          
          
z = (x - u) / s =    0.340685623      
          
Thus, using a table/technology, the left tailed area of this is          
          
P(z <   0.340685623   ) =    0.633329869 [ANSWER]

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23.

We first get the z score for the critical value. As z = (x - u) / s, then as          
          
x = critical value =    33      
u = mean =    32      
          
s = standard deviation =    0.9      
          
Thus,          
          
z = (x - u) / s =    1.111111111      
          
Thus, using a table/technology, the right tailed area of this is          
          
P(z >   1.111111111   ) =    0.133260263 [ANSWER]

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