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In 2010, ~25% of households in the USA had exactly 2 children. In 2010, 4 out of

ID: 3022531 • Letter: I

Question

In 2010, ~25% of households in the USA had exactly 2 children. In 2010, 4 out of 10 households in the USA rented their place of residence. In 2010, 0.06 households in the USA were in New York State. What is the probability that you lived in a household in New York State in a rental with two children?

In 2010, ~25% of households in the USA had exactly 2 children. In 2010, 4 out of 10 households in the USA rented their place of residence. In 2010, 0.06 households in the USA were in New York State. What is the probability that you lived in a household in New York State in a rental with two children?

Explanation / Answer

you have to multiply the probabilities because is "and", you live and a household and is a rental and you have two children. If theres a exclusion like "you have three or two childrend" it will be a sum, but is not the case.

so you have

P(household)= 0.25

P(rental) = 4/10= 0.40

P(new york)= 0.06

P total= 0.25*0.06*0.40= 0.006

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