Determine the probability that at least 2 people in a room of 10 people share th
ID: 3022450 • Letter: D
Question
Determine the probability that at least 2 people in a room of 10 people share the same birthday, ignoring leap years and assuming each birthday is equally likely, by answering the following questions: Compute the probability that 10 people have different birthdays. The complement of "10 people have different birthdays" is "at least 2 share a birthday". Use this information to compute the probability that at least 2 people out of 10 share the same birthday. The probability that 10 people have different birthdays is . (Round to four decimal places as needed.)Explanation / Answer
PROBABILITY OF HAVING SAME BDAY = 1/365
PROBABILITY OF HAVING DIFFERENT BDAY = 364/365
A) NOW THE PROBABILITY THAT ALL 10 HAVE DIFFERENT BDAY = (364/365)^10 = 0.972
B) PROBABILITY THAT AT LEAST 2 HAVE SAME BDAY = 1 - P(NO SAME BDAY) ( AS ONLY 0 WILL BE COUNTED BACUASE TO SHARE AT LEAS 2 PEOPLE ARE REQUIRED)
PROBABILITY = 1 - 0.972 = 0.228
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