Due in 3 hours, 3 minutes. Due Thu 10/12/2017 11:59 The population of a town tod

Question

Due in 3 hours, 3 minutes. Due Thu 10/12/2017 11:59 The population of a town today is 42000 people. a. If the population decreases with a constant rate of change and the decrease is 6% in the first year, what will the town's population be in 8 years? (Round to the nearest person) 25602 ,, Preview b. If the population decreases with a constant percent change and the decrease is 6% in the first year, what will the town's population be in 8 years? (Round to the nearest person) 42008 Preview Points possible: 8 This is attempt 2 of 5. Score on last attempt: 0. Score in gradebook: 0 Licen Submit

Explanation / Answer

PArt A :

In the first yr, it decreased by 6%,
i.e by 0.06 * 42000, ie 2520

so, in 8 yr it iwll go down by 2520*8 = 20160

So, population at the end of 8 yrs :
42000 - 20160

21840
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Part B :

Initial population, P = 42000

Decrease is 6%
So, at the endof the yr, 94%, i.e 0.94 remains

So, equation is :

A = 42000(0.94)^t

Now, plug in t = 8 for the 8 years :
A = 42000(0.94)^8
A = 25601.8954187254272

25602 ppl

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