a. How much greater is the area of a square with a side length of 7 inches than

Question

a. How much greater is the area of a square with a side length of 7 inches than the area of a circle with a radius of 4 inches? square inches b. How much greater is the area of a circle with a radius of 8.7 inches than the area of a square with a side length of 4.5 inches? square inches c. Suppose the area of a circle with radius r is larger than the area of a square with side length l. Define a formula that expresses D, how much greater the area of a circle with radius r is than the area of a square with side length l, in terms of r and l. (That is, write a formula that expresses D in terms of r and l.)

Explanation / Answer

Solutions:

Ares of square = side^2

Area of cirle = pi r^2

Difference in area = 7^2 - 3.14 * 4^2

= -1.24 square inches

(b) again Difference = area of circle - area of square = pi * r^2 -side^2 '

= 3.14 * 8.7^2 - 4.5^2

= 217.1416

(c) Difference area that is greater = area of circle - area of square

= r^2 - l^2

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