thank you in advance! 7 3,5 028 Suppose that in a certain biology lab experiment
ID: 3016603 • Letter: T
Question
thank you in advance!
Explanation / Answer
N(T) = - 2T^2 + 250T - 5000
T(t) = 10t + 50
N[T(t)] = - 2 ( 10t + 50)^2 + 250 (10t+50 ) - 5000
= -2 ( 100t^2 + 1000t + 2500 ) + 2500t + 12500 - 5000
= -200t^2 - 2000t - 5000 + 2500 t + 12500 - 5000
combining like terms
= - 200t^2 + 500t + 2500
a) bacteria present at t = 0 hr
= -200(0)^2 + 500 (0) + 2500
= 2500 bacteria
b) t = 2
= -200(2)^2 + 500 (2) + 2500
= 2700 bacteria
c) t = 5
- 200(5)^2 + 500(5) + 2500
= 0
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