5.) 2, 1, 5, 3,4 A dialysis bag (permeable to water but not to sucrose) is fille
ID: 301037 • Letter: 5
Question
5.) 2, 1, 5, 3,4 A dialysis bag (permeable to water but not to sucrose) is filled with a sucrose solution and placed in a beaker containing 30% sucrose solution. The bag's initial weight was 15 g, and after 15 minutes it weighed 17 36. g. Calculate percent change in weight of the dialysis bag. After 45 minutes, the same bag weighed 20g. What is the cumulative percent change in weight of the bag at that point? M-17% Assume that you have a 20 M glycerol stock solution. You need to make 5 different solutions for your experiment: 0 M or no glycerol, 2.5 M glycerol, 5 M glycerol, 7.5 M glycerol and 10 M glycerol. In each experiment you will need to make 50 ml of the diluted solution. Show your calculations for each solution: 37. Final concentration of solution 0 M glycerol 5 M glycerol 10 M glycerol Amount of 20 M glycerol stock solution Final volume of the solution Amount of waterExplanation / Answer
36. Water from the sucrose solution will move into the dialysis bag containing sucrose to increase the weight of bag as time progresses.
Percent change in weight of dialysis bag=
(Weight of bag at 15 min- Initial Weight of bag at 0 min)/Initial Weight of bag at 0 min X 100
= (17g-15g)/15g X 100= 2/15 *100= 13.33 %
Cumulative Change in Weight of dialysis bag=
(Final weight of bag at 45 min- Initial Weight of bag at 0 min)/Initial weight of bag at 0 min X 100
= (20g-15g)/15g X 100= 5g/15g X 100= 33.33%
37. Final volume= 50 ml
C1=Initial concentration of glycerol stock solution= 20 M glycerol
V2= Final volume of diluted solution= 50 ml
V1= volume of 20 M glycerol to be added=?
C2= Final concentration of glycerol in diluted solution
The formula C1V1= C2 V2 is used
1) 0 M Glycerol
C2 = 0 M
C1V1=C2V2
20M * V1= 0 M * 50 ml
V1= 50 X 0/20= 0 ml
50 ml of water is added
2) 2.5 M glycerol
C1V1=C2V2
20M *V1= 2.5 M * 50 ml
V1= 2.5M * 50 ml/20M= 6.25 ml
Amount of water added= 50-6.25= 43.75 ml
3) 5 M glycerol
C1V1=C2V2
20M *V1= 5 M * 50 ml
V1= 5M * 50 ml/20M= 12.5 ml
Amount of water added= 50-12.5= 37.5 ml
4) 7.5 M glycerol
C1V1=C2V2
20M *V1= 7.5 M * 50 ml
V1= 7.5 M * 50 ml/20M= 18.75 ml
Amount of water added= 50-18.75= 31.25 ml
5) 10 M glycerol
C1V1=C2V2
20M *V1= 10 M * 50 ml
V1= 10 M * 50 ml/20M= 25 ml
Amount of water added= 50-25= 25 ml
Final concentration of solution
Amount of 20M glycerol stock solution
Amount of water
Final volume of solution
0 M
0 ml
50 ml
50 ml
5 M
12.5 ml
37.5 ml
50 ml
10 M
25 ml
25 ml
50 ml
Final concentration of solution
Amount of 20M glycerol stock solution
Amount of water
Final volume of solution
0 M
0 ml
50 ml
50 ml
5 M
12.5 ml
37.5 ml
50 ml
10 M
25 ml
25 ml
50 ml
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