An investor has two money-making activities, coded Alpha and Beta, available at
ID: 3004031 • Letter: A
Question
An investor has two money-making activities, coded Alpha and Beta, available at the beginning of each of the next four years. Each dollar invested in Alpha at the beginning of a year returns $1.40 two years later (in time for immediate reinvestment). Each dollar invested in Beta at the beginning of a year returns $1.80 three years later. A third investment possibility, construction projects, will become available at the beginning of the second year and will be available at the beginning of the third and fourth years also. Each dollar invested in construction returns $1.20 one year later. The investor starts with $10,000 at the beginning of the first year and wants to maximize the total amount of money he has available at the end of the fourth year.
Explanation / Answer
first year:
code Alpha and Beta both are available for first year
if we start with Alpha, which returns $1.40 two years later
Initial deposit= $10000
so amount available for third year = $10000x$1.40 = $14000
two years remaing and Beta is for 3 years so only choice are to use Alpha or construction projects
if we use Alpha in 3rd year then amount at the end of 4th year=$14000x$1.40 = $19600
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if we use construction projects whose duration is for 1 year then we need to use it in 4th year too
hence amount at the end of 4th year=$14000x$1.20x$1.20 = $20160
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if we start with Beta in first year whose duration is 3 years
so amount at the end of 3rd year=$10000x$1.80=$ 18000
1 year is remaing so we can use only construction projects
hence amount at the end of 4th year=$18000x$1.20 = $21600
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we got 3 cases in which maximum return is $21600
Hence to maximize total amount of money, you should invest $10000 in Beta for first 3 years then reinvest it into construction projects.
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