Brown fur stripes (autosomal recessive) is found in 13% of the squirrels in Yell

Question

Brown fur stripes (autosomal recessive) is found in 13% of the squirrels in Yellowstone National Park. Black is the dominant stripe color. Answer the following questions about this population, assuming this population of squirrels is in Hardy-Weinberg equilibrium with respect to fur stripes.

a) What are the frequencies of the brown stripe (b) and black stripe (B) alleles? b) What is the frequency of heterozygotes? In the next generation, what is the proportion of heterozygote matings? (Hint: You will need to use the product rule.) d in the next generation, what proportion of squirrels will be brown stripe progeny resulting from heterozygote matings? (Hint: You will need to use the product rule.)

Explanation / Answer

a). Given that the brown stripes (bb) are found in 13% of squirrels. Means, 13 in 100

The frequency of bb or q2 = 13/100 = 0.13

The frequency of recessive allele, b or q = 0.3605

As the population is in H-W equilibrium, p+q = 1

Thus, the frequency of dominant allele B or p = 1-0.3605 = 0.6395

b). The frequency of heterozygotes is, 2pq = 2*0.6395*0.3605 = 0.4610

c). In the next generation, the proportion of heterozygous mating’s is = The probability of the male to be a heterozygote* the probability of female to be a heterozygote = ½*0.4610*1/2*0.4610 = 0.0531

Related Questions

Navigate

• Browse (All)
• Browse B
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.