1. H20 enters a tank with a velocity of 20 m/s at a temperature and pressure of

Question

1. H20 enters a tank with a velocity of 20 m/s at a temperature and pressure of 600 C and 20 bar, respectively, through a pipe with a cross-sectional area of 10 x 10^-3 m^2. A spout at the bottom of the tank allows H20 to leave at a velocity of 1 m/s through an opening with an area of 6 x 10^-3 m^2. The exit temperature and pressure is 150 C and 10 bar, respectively. At the inlet and exit of the tank, determine the mass flow rate, each in kg/s. Find the time rate of change of mass contained within the tank, in kg/s.

Explanation / Answer

m = Volume flow rate * density

Volume flow rate = Velocty(V) * Area of cross section(A)

density = 1/specific volume at given conditions = 1/v

therefore

m = V*A/v

For inlet v = 0.1996 (from superheated steam table)

min = 10*0.01/0.1996 = 1.002 kg/s

for outlet v = 1.091 ( from temperature based saturated steam table)

mout = 1*0.006/1.091 = 5.5 * 10-3

change of mass = min - mout = 0.9965 kg/s

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