An insulated rigid tank is divided into two equal parts initially by a partition

Question

An insulated rigid tank is divided into two equal parts initially by a partition. Initially, one part contains 5 kg of air at 800 kPa and 75 C and the other part is evacuated. The partition is now removed and the air expands into the entire tank. Determine the size (volume) of the tank and the final pressure in the tank.

An insulated rigid tank is divided into two equal parts initially by a partition. Initially, one part contains 5 kg of air at 800 kPa and 75 C and the other part is evacuated. The partition is now removed and the air expands into the entire tank. Determine the size (volume) of the tank and the final pressure in the tank.

Explanation / Answer

INITIAL

m = 5 kg

P1 = 800 kPa

T1 = 75 C = 348 K

P1*V1 = m*R*T1

800*V1 = 5*0.287*348

V1 = 0.624 m^3

Since it is equally divided

VOLUME OF TANK = 2*V1 = 1.248 m^3

FINAL

V2 = 1.248 m^3

When the volume is opened

dU = 0

m*Cp*(T2-T1) = 0

T2 = T1

Therefore

P2 = 1/2*P1 = 400 kPa

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