Preview File Edit View Go Tools Window Help 96% CI, Tue 9:29 PM Q. E Fundamental

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Preview File Edit View Go Tools Window Help 96% CI, Tue 9:29 PM Q. E Fundamentals of Thermodyna... x 134a Enters A... x Steam flows steadily throu... x Homework Help Ask A Qu... x http ME 301 5.pdf (page 1 of 2) O O a UT DIET My ANG Anderson 2. Steam flows steadily through an adiabatic turbine at a rate of 900 kg/min. The inlet conditions of Map the steam are 5 MPa, 400 °C, and 70 m/s, and the exit conditions are 50 kPa, 85 percent quality, expa Previous Next and 40 m/s. Determine (a) the change in kinetic energy, (b) the power output, and (c) the turbine inlet area. (20 points) 5 MPa 400 °C VI 70 m/s STEAM 900 kg/min 2 50 kPa 40 m/s V2 Map

Explanation / Answer

a. Flow rate of steam=900 kg/min=900/60=15 kg/sec

Change in KE=0.5*mass flow rate*(vf2-vi2)

                                =0.5*15*(402-702)

                                =-24750 W    [-ve sign shows KE decreases]

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b. Enthalpy of steam at inlet=enthalpy of superheated steam at 5Mpa and 400?

                                                =3196.6 kJ/kg

Enthalpy of outlet steam=Enthalpy of saturated steam at 50 kPa, 85% quality

                                                =640.185 +0.85(2748.11-640.185)

                                                =2431.9 kJ/kg

[ALL DATA ARE FROM STEAM TABLE]

Change in enthalpy=2431.9-3196.6=-764.7 kJ/kg

Power from turbine=-[mass flow rate*change in enthalpy +Change in KE]

                                =15*764.7+24.750=11495.25 kW

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c. Volume flow rate=Mass flow rate*specific volume=15*0.05784=0.8676 m3/sec

Area of flow=volume flow rate/velocity

                =0.8676/70=0.0124 m2

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