what are the answers of part a and b? You apply 200 N force (as shown below) to

Question

what are the answers of part a and b?

You apply 200 N force (as shown below) to turn the crank. To make this problem more meaningful, I can even add that the crank won't turn unless you apply 40 N.m about the rotating axis. What is the moment due to F about point 0? What is the useful moment generated by the 200 N force? ("useful" means that the moment contributes to the rotation of the crank) Will you be able to turn the crank? What do you think happened to the "unuseful" part of the moment? Let's say that due to the manufacturing defect, the location O will break if the bending moment at O is greater than 45 N.m Will it break or not? This is tricker than you think.

Explanation / Answer

F=200*(cos120 i + cos 60 j + cos45 k) = 200*(-0.5 i +0.5j +0.707 k)

Moment abt O = r X F = 0.3 j X (-0.5i+0.5j+0.707k) *200 = 30 k + 42.42 i

useful moment will be Mz = 30

yes the crank will turn

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