A cylindrical specimen of a brass alloy 9.1 mm (0.36 in.) in diameter and 93.0 m

Question

A cylindrical specimen of a brass alloy 9.1 mm (0.36 in.) in diameter and 93.0 mm (3.66 in.) long is pulled in tension with a force of 3680 N (827.3 lbf); the force is subsequently released.
(a) Compute the final length of the specimen at this time. The tensile stress-strain behavior for this alloy is shown in Animated Figure 6.12.
(b) Compute the final specimen length when the load is increased to 24200 N (5440 lbf) and then released.

What is the final length, in mm, of the specimen after the 3680 N is released?

the answer for is 56.5816

Explanation / Answer

Youngs modulus E = stress / strain

from the graph you have to get this value. You havent provided me with a figure. so I am just explaining the steps

E = stress/strain

stress = F/A = force applied / area of crosssection

strain = change in length / initial negth

F is given , diameter is give so we can calculate area

initial length is given

we have to find the final length .

Let me know if you need any explanation

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