For each state, indicate if the fluid is compressed liquid, saturated mixture, o
ID: 2993790 • Letter: F
Question
For each state, indicate if the fluid is compressed liquid, saturated mixture, or superheated vapor. Show the state on a T- v diagram with the vapor dome and a constant
pressure line passing through the state. Then determine the requested properties using the steam tables in the textbook. If you need to interpolate between values from the steam tables, show the interpolation table as done on page 86 of the text and Homework 1 Problem 4. Do not use the Problem Solving Method for this problem.
a. Water, T=534 K, P=2.0 MPa. Find v, u, h.
b. Water, T=410 K, saturated mixture at x=0.3. Find P, v, u, h. c. Water, P=10.0 MPa, v=0.03 m3/kg. Find T, u, h.
d. Water, P=1.0 MPa, u=1500 kJ/kg. Find T, v, h.
Problem Solving Method:
. Use the bold titles below as headings in your solutions.
KNOWN: In your own words, briefly state the geometry and the given quantities of the
problem.
FIND: What is unknown that we are asked to find.
SKETCH: Include a sketch for each problem. Also include a P-v, or T-s curve as appropriate.
ASSUMPTIONS: These need to be justified if they are atypical.
PROPERTIES: List the properties that were used and reference the table in which the values
were found. For example:
Superheated water, Table D.3I h(480K, 1.0MPa)=2844.7 kJ/kg
ANALYSIS: Solve the problem, step-by-step, and always include units. Give the final
answer to four significant digits and box the final answer.
DISCUSSION: Discuss your results. Are the results expected? Miscalculations can lead to
unrealistic results. Indicate if you feel that your answer is not realistic. How do the results
compare to other conditions such as standard atmospheric conditions, internal combustion
Explanation / Answer
a)From the steam tables
At P = 2 MPa and T = 534 K = 261 deg
At P = 2 MPa and T1 =250 deg
v1 = 0.1117 m^3/kg
u1 = 2682 kJ/kg
h1 = 2905 kJ/kg
At P =2 MPa and T2 =300 deg
v2 =0.1255
u2 = 2773
h2 = 3023
Now At T = 261 deg
By linear Interpolating
(T-T1)/(T2-T1) = (v-v1)/(v2-v1)
Similarly for others
v = 0.1146 m^3/kg
u = 2701 kJ/kg
h = 2930 kJ/kg
SUPERHEATED VAPOR
b) At T = 410 K and x = 0.3
P = 331.7 kPa
vf = 0.001077
vg = 0.5514
uf = 575.9
ug = 2547
hf = 576.2
hg = 2730
We know
v =x*vf + (1-x)*vg
u =x*uf + (1-x)*ug
h =x*hf + (1-x)*hg
Solving
v = 0.1662
u = 1167
h = 1222 kJ/kg
LIQUID-VAPOR MIXTURE
c)Similar analysis
At P = 10 MPa
v = 0.03
T = 727 K
u = 2952
h = 3252
Dense Fluid
d)At P = 1 MPa and u = 1500
T = 453 K
h = 1580
v = 0.07952
LIQUID-VAPOR MIX
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