PLEASE HELP Assume the wood has 25% moisture and 0.8% ash on an as-received basi

Question

PLEASE HELP

Assume the wood has 25% moisture and 0.8% ash on an as-received basis. The bulk density of stacked wood is 45% of the density of the wood. Assume that the dry. ash-free composition of the wood is 51.2%, 5.8%, 42.4%, 0.6%, and 0% for C. H. O, N, and S, respectively. The dry density of the wood is 640 kg/m3. The dry, ash-free HHV of the wood is 19.7 MJ/kg. What is the as-received LHV of the wood (MJ/kg)? What is the as-received density of the wood (kg/m3)? What is the as-received bulk density of the wood (kg/m3)? What is the bulk volume (L) and

Explanation / Answer

LHV = HHV

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