I am trying to find the force P that it would take to set the two cylinders in t

Question

I am trying to find the force P that it would take to set the two cylinders in the picture in motion. I know to treat them as a single rigid body and I know that you have to change the friction force to the co-effcient of friction multiplied by the normal force since there are too many unkown for basic moment and force equations. I just need help with the overall process as well as figuring out the internal forces where the weld is. I know it is fixed so that would mean theres a perpindicular force as well as a moment but I need help with going through this problem to solve for these things. I don't know if it matters but in the previous problem the cylinders were not welded together and the co-effiecent of friction was .3 thanks!

Explanation / Answer

Since they are welded, they will slide and not rotate.

Also friction force at the interface of both the cylinders will be zero as they are welded (no relative motion).

Fric force = (ama + bmb)g Cos

P = (ama + bmb)g Cos + (ma + mb)g Sin

Normal force at the weld = Force due to B = mbg Sin

Moment at weld = (amara + bmbrb)g Cos

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