Use the equations below. (Note that the direction is indicated by the sign in fr

Question

Use the equations below. (Note that the direction is indicated by the sign in front of the equations.)
x = (0.0571 m) cos(3.690t + 0.16pi)
v = -(0.211 m/s) sin(3.690t + 0.16pi)
a = -(0.778 m/s2) cos(3.690t + 0.16pi)
(a) Determine the first time (greater than zero) that the position is at its maximum value.


s Set the argument of the sine or cosine function to the value that satisfies the stated condition, and solve for the time.

(b) Determine the first time (greater than zero) that the velocity is at its maximum value.


s Set the argument of the sine or cosine function to the value that satisfies the stated condition, and solve for the time.

Explanation / Answer

Position is max ==> cos theta = 1 ==> 3.69t +0.16pi = 0,2pi etc 0 cannot be as theta >1 Hence 3.69t +0.16pi = 2pi ==>t = 1.56 s Similarly for velocity we have 3.690t + 0.16pi = 3pi/2 ==>1.14 sec

Related Questions

Navigate

• Browse (All)
• Browse U
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.