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A0.71-kg block attached to a spring with force constant112N/m is free to move on

ID: 2992787 • Letter: A

Question

A0.71-kg block attached to a spring with force constant112N/m is free to move on a frictionless, horizontal surface as in the figure below. The block is released from rest after the spring is stretched 0.13 m.

(a) At that instant, find the force on the block.

magnitude N direction ---Select---leftright A0.71-kg block attached to a spring with force constant112N/m is free to move on a frictionless, horizontal surface as in the figure below. The block is released from rest after the spring is stretched 0.13 m. (a) At that instant, find the force on the block.

Explanation / Answer

a) Force = kx = 112*0.13 = 14.56 N to the left ma = kx a = 14.56/0.71 = 20.5 m/s^2 b) Force = kx = 112*0 = 0 a = 0 c) Force = kx = 112*0.13 = 14.56 N to the right ma = kx a = 14.56/0.71 = 20.5 m/s^2

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