Apply the particle under a net force model to the block in the horizontal direct
ID: 2992428 • Letter: A
Question
Apply the particle under a net force model to the block in the horizontal direction:
(1) ?Fx = F cos(?) - fk - T = m2ax = m2a
Apply the particle in equilibrium model to the block in the vertical direction:
(2) ?Fy = n + F sin(?) - m2g = 0
Apply the particle under a net force model to the ball in the vertical direction:
(3) ?Fy = T - m1g = m1ay = m1a
Solve Equation (2) for n:
n = m2g - F sin(?)
Substitute n into fk = ?kn from the above equation:
(4) fk = ?k (m2g - Fsin(?))
Substitute Equation (4) and the value of T from Equation (3) into Equation (1):
F cos(?) - ?k(m2g - Fsin(?)) - m1(a + g) = m2a
Solve for a in terms of ?k, m1, m2, g, and ?:
a =
Explanation / Answer
FCos - k(m2g - FSin) - m1g = (m1+m2)a
a = [FCos - k(m2g - FSin) - m1g]/(m1+m2)
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