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FOR BOTH CIRCUITS Derive the transfer functions. Find the frequency where the ou

ID: 2990591 • Letter: F

Question

FOR BOTH CIRCUITS

Derive the transfer functions.

Find the frequency where the output voltage is 90 degrees out of phase with the input

voltage. Find the amplitude of the output voltage at this frequency.

Find the frequency where the amplitude of the output voltage is 1/3 that of the input

voltage. Find the phase difference between the input and output voltages.

Are the frequencies found in step 2 and 3 the same?Please explain.

FOR BOTH CIRCUITS Derive the transfer functions. Find the frequency where the output voltage is 90 degrees out of phase with the input voltage. Find the amplitude of the output voltage at this frequency. Find the frequency where the amplitude of the output voltage is 1/3 that of the input voltage. Find the phase difference between the input and output voltages. Are the frequencies found in step 2 and 3 the same?Please explain.

Explanation / Answer

circuit 1 :

call the middle node V , then applying nodal analysis to it u get :

(Vin - V) / R = V (Cs) + (V - Vout)/R

multiplying by R u get :

Vin - V = (RCs) V + (V - Vout)

Vin = (2 + RCs) V - Vout ... (1)

and nodal at right node gives :

(V - Vout)/R = (Cs) Vout

so V - Vout = (RCs) Vout

hence V = (RCs + 1) Vout ... (2)

substituting for V in eqn (1) gives :

Vin = (2 + RCs) (RCs + 1) Vout - Vout

=> Vout [ (2 + RCs) (RCs + 1) - 1] = Vin

so H1(s) = Vout / Vin = 1 / [ (RC)2 s2 + 3RCs + 1]

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circuit 2 :

call the middle node V , then applying nodal analysis to it u get :

Cs (Vin - V) = V /R + Cs (V - Vout)

multiplying by R u get :

(RCs)(Vin - V) = V + (RCs)(V - Vout)

Vin - V = V / (RCs) + V - Vout

=> Vin = V (2 + 1/RCs) - Vout ... (1)

and nodal at right node gives :

(Cs)(V - Vout) = Vout /R

so (RCs) (V - Vout) = Vout

hence V = Vout (1 + 1 / RCs) ... (2)

substituting for V in eqn (1) gives :

Vin = Vout (1 + 1 / RCs) (2 + 1/RCs) - Vout

=> Vin = Vout [ (1 + 1 / RCs) (2 + 1/RCs) - 1]

=> Vout / Vin = 1 / [ (1 + 1 / RCs) (2 + 1/RCs) - 1]

mult by (RCs / RCs) u get :

Vout / Vin = RCs / [ (RCs + 1) (2 + 1/RCs) - RCs]

=> Vout/Vin = RCs / [ 2RCs + 1 + 2 + 1/RCs - RCs ]

= RCs / [ RCs + 3 + 1/RCs ]

=> H2(s) = (RC)2s2 / [ (RC)2s2 + 3RCs + 1]