(1 pt) DC Imperfections 3 8e8e989-34a6 A noninverting amplifier with a closed-lo
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(1 pt) DC Imperfections 3 8e8e989-34a6 A noninverting amplifier with a closed-loop gain of 301 V/Vis designed using an op amp having an input offset voltages of 4.5 mv and output saturation levels of t 13 v What is the maximum amplitude sine wave that can be applied at the input without the output clipping? 3 webwork uml.edu/webwork2 iWMM Maximum amplitude is ma CI Ri HT f he amplifier is capacitively coupled in the manner indicated in the shown Figure what would the maximum possible amplitude be? Maximum amplitude is maExplanation / Answer
1) If the maximum output is 13 V, the the maximum input is 13/301 = 43.189 mV. Of that 4.5 mV is the o?set,
leaving a maximum signal amplitude of (43.189-4.5)=38.689 mV.
2)If the ampli?er is capcitively coupled on the input we can use superposition for the analysis, adding the DC o?set voltage source and the AC input source. Since for the DC source the gain path has a open circuit there will be no current ?owing in it, and the output voltage from the o?set is equal to the o?set voltage, 4.5 mV. The result is that the AC source can supply up to 13 V ? 4.5 mV, e?ectively 13 V on the output, which corresponds to 43.189 mVon the input. This works when the input source is an AC signal only
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