Question 1: Let d be a positive integer and consider any set A of d+1 positive i
ID: 2984613 • Letter: Q
Question
Question 1: Let d be a positive integer and consider any set A of d+1 positive integers. Show that there exists two different numbers x, y∈A so that x mod d=y mod d and x not equal to y.Question 2: 1. Say that you take n+ 1 numbers out of 1,2, . . . ,2n. Show that there will be two consecutive numbers
2. Say that you take n+ 1 numbers out of 1,2, . . . ,2n. Show that there will be two numbers x, y so that gcd(x, y) = 1
Question 1: Let d be a positive integer and consider any set A of d+1 positive integers. Show that there exists two different numbers x, y∈A so that x mod d=y mod d and x not equal to y.
Question 2: 1. Say that you take n+ 1 numbers out of 1,2, . . . ,2n. Show that there will be two consecutive numbers
2. Say that you take n+ 1 numbers out of 1,2, . . . ,2n. Show that there will be two numbers x, y so that gcd(x, y) = 1
Question 2: 1. Say that you take n+ 1 numbers out of 1,2, . . . ,2n. Show that there will be two consecutive numbers
2. Say that you take n+ 1 numbers out of 1,2, . . . ,2n. Show that there will be two numbers x, y so that gcd(x, y) = 1
Explanation / Answer
1. There are only d remainder classes modulo d.Since there are d+1 positive integers,by Pigeon Hole Principle there should be two positive integers which have same remainder modulo d
Hence the problem
2. (i) Divide the numbers 1,2,...,2n in to n disjoint sets {1,2}, {3,4},...{2n-1,2n}.Since n+1 numbers are selected there is atleast one set from which two are selected by PHP
Hence there will be two consecutive numbers.
(ii) By part i there are two consecutive numbers in the n+1 numbers selected.These have gcd 1.
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