Three cylinders of an ideal gas are connected together through closed valves. Cy

Question

Three cylinders of an ideal gas are connected together through closed valves. Cylinder A holds 20 liters at 60 atmospheres pressure Cylinder B holds 30 liters at 30 atmospheres Cylinder C holds 50 liters at 40 atmospheres The valves are opened and the cylinders contents allowed to mix. Assuming the temperature is the same throughout what is the final pressure in the cylinders?

Explanation / Answer

Number of moles of the gas in Cylinder A = (60 x 20) / RT = 1200/RT ---> 1 Number of moles of the gas in Cylinder B = (50 x 40) / RT = 2000/RT ---> 2 Number of moles of the gas in Cylinder C = (30 x 30) / RT = 900/RT ---> 3 On mixing the number of moles do not change, and hence the total number of moles = sum of (1), (2) and (3) = 4100/RT Also the volume now becomes 30 + 20 + 50 = 100 liters since everything is mixed. Therefore pressure P = nRT/V = ((4100/RT) x RT)/100 = 41 atmospheres Here R is the gas constant and the temperature is T which is assumed constant throughtout as stated in the question.

Related Questions

Navigate

• Browse (All)
• Browse T
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.