As follows, Consider the function = u + iv with the real and imaginary parts exp
ID: 2968499 • Letter: A
Question
As follows,
Explanation / Answer
if f is differentiable then we can use cauchy riemenn equation
u(r) = v(theta)/r--------------------------(a)
and u(theta)/r = -v(r)---------------------(b)
z= u+iv = e^-i(theta)
there fore f'(z) = df/dx = du/dx + dv/dy
= e^-(theta) ( u(r ) + i v(r))---------------(1)
(1) can be also written as
z= re^-i(theta)
hence 1 becomes = -i/z * (u(theta) + i v(theta)) (from a and b)
hence proved
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