{Exercise 13.13} The following data are from a completely randomized design. {Ex
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Question
{Exercise 13.13}
The following data are from a completely randomized design.
{Exercise 13.13}
The following data are from a completely randomized design.
- At the = .05 level of significance, can we reject the null hypothesis that the means of the three treatments are equal?
Compute the values below (to 2 decimals, if necessary).
Sum of Squares, Treatment Sum of Squares, Error Mean Squares, Treatment Mean Squares, Error
Calculate the value of the test statistic (to 2 decimals).
The p-value is Selectless than .01between .01 and .025between .025 and .05between .05 and .10greater than .10Item 6
What is your conclusion?
Select Conclude not all treatment means are equal Do not reject the assumption that the treatment means are equalItem 7
- Calculate the value of Fisher's LSD (to 2 decimals).
Use Fisher's LSD procedure to test whether there is a significant difference between the means for treatments A and B, treatments A and C, and treatments B and C. Use = .05.
Difference Absolute Value Conclusion A - B SelectSignificant differenceNo significant differenceItem 10 A - C SelectSignificant differenceNo significant differenceItem 12 B - C SelectSignificant differenceNo significant differenceItem 14
- Use Fisher's LSD procedure to develop a 95% confidence interval estimate of the difference between the means of treatments A and B (to 2 decimals). Since treatment B has the larger mean, the confidence interval for the difference between the means of treatments A and B (A - B) should be reported with negative values.
( , )
Explanation / Answer
1. Sum of Squares, Treatment = 570
Sum of Squares, Error = 66
Mean Squares, Treatment = 285
Mean Squares, Error = 5.5
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