Mr. X moved to Atlanta and a bought a car on December 1 last year. According to

Question

Mr. X moved to Atlanta and a bought a car on December 1 last year. According to Georgia laws, he should have registered it until December 31 last year, but Mr. X did not do in order to avoid expensive repairs needed to pass on the emission test. The tag is missing, and the probability that the police stops him in a month is 155. Calculate the probability that the police stopped him until the 1st of this month in exactly4months. What is the probability that the last month was the third one in which the police stopped him?

Explanation / Answer

In a year we have 12 months. a) Probability that the police stoppedhim until the 1st of this month ion exactly 4 months That is P(x=4) = C(12,4) (0.15)^4*(0.85)^8 =0.06828 --------------------------------------------------------------- b) last month is the 3rd one in which police stopped him. P(x=3) = C(11,3) (0.15)^3(0.85)^8 =0.1517

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