2. Given a level of confidence of 95% and a population standard deviation of 9,

Question

2. Given a level of confidence of 95% and a population standard deviation of 9, answer the following:
(A) What other information is necessary to find the sample size (n)?
(B) Find the Maximum Error of Estimate (E) if n = 56. Show all your calculations. Show all work.

3. A sample of 106 golfers showed that their average score on a particular golf course was 87.98 with a standard deviation of 5.39.
Answer each of the following (show all work and state the final answer to at least two decimal places.):
(A) Find the 90% confidence interval of the mean score for all 106 golfers.
(B) Find the 90% confidence interval of the mean score for all golfers if this is a sample of 130 golfers instead of a sample of 106.
(C) Which confidence interval is larger and why?

Explanation / Answer

sample of 106 golfers showed that their average score on a particular golf course was 87.98 with a standard deviation of 5.39. A) Find the 90% confidence interval of the mean score for all 106 golfers. ME = 1.645[5.39/sqrt(106)] = .8612 CI: 87.98-.8612

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