PART 1: Rework problem 29 in section 4.1 of your text, involving the flipping of

Question

PART 1:

Rework problem 29 in section 4.1 of your text, involving the flipping of
one of three coins. Assume that you have two fair coins and an unfair coin
with Pr[H]=5/6. You randomly select one of these coins, and flip it twice. A random variable X is defined to be the number of heads you observe.


There are 3 values are possible for the random variable

PART 2:

Fill in the table below to complete the probability density
function. Be certain to list the values of X in ascending order.

Value of X Probability

Explanation / Answer

P(H=0)=2*(1/3)*(1/2)*(1/2)+(1/3)*(1/6)*(1/6) P(H=1)=4*(1/3)*(1/2)*(1/2)+2*(1/3)*(5/6)*(1/6) P(H=2)=2*(1/3)*(1/2)*(1/2)+(1/3)*(5/6)*(5/6) Well I tried to include a tree diagram to help you understand, but it's not loading. So sorry abt tht. Anyways the answers oughta be right.

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